A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall.

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#### Solution

Let OA be the wall and AB be the ladder.

Therefore, by Pythagoras theorem,

AB2 = OA + BO

(10 m)^{2} = (8m)^{2} + OB^{2}

100 m^{2} = 64 m^{2} + OB^{2}

OB^{2} = 36 m^{2}

OB = 6 m

Therefore the distance of the foot of the ladder from the base of the wall is 6 m

Concept: Right-angled Triangles and Pythagoras Property

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